Ламерской вопрос, массив unsigned char Опции

[Fortune]

Я с ARM еще не работал, но у меня появились вопросы.
Если обьявить массив типа unsigned char в ОЗУ
сколько будет занимать один элемент в памяти?
Можно ли сделать так, чтобы он занимал 1 байт?
Если нет, то как легче всего это сделать программно.

[DASM]

я смотрел в RAM и вообще причем тут ROM-RAM. Удаляем, как не относящееся к делу

[Andrew2000]

Help на Borland C++ Bulder:

"The Data Alignment options let you choose how the compiler aligns data in stored memory. Word, double word, and quad word alignment force integer-size and larger items to be aligned on memory addresses that are multiples of the type chosen. Extra bytes are inserted in structures to ensure that members align correctly.
...
Byte alignment
When byte alignment is on, the compiler does not force alignment of variables or data fields to any specific memory boundaries. The compiler aligns data at even or odd addresses, depending on the next available address.

While byte alignment produces more compact programs, the programs tend to run slower. The other data alignment options increase the speed at which 80x86 processors fetch and store data.

Word alignment (2-byte)
When word alignment is on, the compiler aligns non-character data at even addresses. Automatic and global variables are aligned properly. char and unsigned char variables and fields can be placed at any address; all others are placed at even-numbered addresses.

Double word (4-byte)
Double word alignment aligns non-character data at 32-bit word (4-byte) boundaries. Data with type sizes of less than four bytes are aligned on their type size.
....
"
и т.д.