Hello dear
if there is no problem please at first download this 2papers of RF circuit design book.

in the first page "The effect of component q on loaded q"
this paragraph shows me that the equivalent of the inductor with series resistor in parallel.
1-what the inductor in parallel shows us?(at resonant and after and befor)

in the next page(2)
how does it draw the equivalent of inductor resistor in scheme 2-16C from 2-16B?because we have only inductor q and capacity in Henry with out resonant frequency?


Thanks

For page 2 : Xp=(L/C)^0.5, and Rp=Xp*Q

Thanks Filippov
but i calculate with your formula.these is the result:
L/C=.2
(.2)^.5=44.72
44.72*10=447.2 not 4.5K
?
in this book doesn't we have
Xp=(L/C)^0.5

It may be, they have maked a mistake. And Q=100?

Xp=wL=1/wC => Xp=(L/C)^0.5

Thanks Filippov
excuse me im newbie in telecommunication electronics.
i can't obtain the equation according my calculateion because i have w^2 could you write is simply?
for everthings

Ok.
w=1/(L*C)^0.5 - Resonancet frequencie
Xp=w*L - characteristic Impedance
Xp=(1/(L*C)^0.5)*L=(L/C)^0.5

Thanks alot dear firend