Цитата(Postoroniy_V @ Jan 23 2013, 03:57)

The "rms" of LSBrms refers to the amount of power in the system noise and the "LSB" in LSBrms refers to the smallest detectable change in voltage. Therefore, the LSBrms gives the power of the system noise in terms of the smallest detectable change in voltage. For example, if we have a 16-bit DAQ board and we are measuring from a range of 0 to 10 volts, then our smallest detectable change in voltage is equal to (range/resolution) = (10/(2^16)) = 0.153 mV. If our LSBrms value for system noise is 0.5, then our system noise is (0.5*0.153) = 0.077 mVrms
Тоесть у меня RMS должен быть 3.5?