Цитата(hankerer @ Apr 28 2018, 02:34)

Hi everybody
how to set the mu of the ferrite ?
1000 is the default value in HFSS.
1 is the default value in CST.
I am very confuse for this setting.
That's because HFSS offers you two methods, either defining the ferrite as a dielectric for lower freq. solutions, or using Kittel theory and Polder tensor, where μ is a kind of proportionality coefficient, or an asymptotic value (for example, 0.9, because Polder's μ itself has an asymptote of 1). This peculiar case is not clearly explained in the manual, and the code is a secret of developers. But trust me, it gives exactly the same solution that paper calculations without additional boundary conditions would give. I.e. you technically can see there an unpinned surface magnetostatic mode (fundamental), but not an exchange mode. I am not sure about volume magnetostatic waves, because pinning b.condition is important there and I did not try checking it.
I am not sure about CST. Our team was using HFSS as a universal tool, and COMSOL for more precise multi-mode solving of complex geometries.
Looking at the photo, I see Magnetic saturation (aka Mo, or Ms) is zero. In garnet RF ferrites it generally lies between 500G and 2000G. Therefore, you have a dielectric case on the screenshot. Put there your Ms, and define μ between 0.9 and 1 (start from 1 and tweak it till matched with experiment). Define reasonable Delta H for avoiding unpleasant errors from infinite MS-mode propagation.